comparator in ex23 and ex25
zhongwei Qi
zhongwei_qi at yahoo.com
Sun Jul 7 17:46:31 EDT 2002
Hi,
I am confused by the comparator function for ex23 and
ex25. I think it should be:
return ( 1.0-exp( -(a.gene(0) - b.gene(0)) *
(a.gene(0) - b.gene(0)) / 1000.0));
Any one could give me a clarification about it?
Thanks,
Zhongwei
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