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<DIV dir=ltr align=left><SPAN class=794033506-16082006><FONT face=Arial
color=#0000ff size=2>No definitely not - there is no grandfather clause with
substitution. </FONT></SPAN></DIV>
<DIV dir=ltr align=left><SPAN class=794033506-16082006><FONT face=Arial
color=#0000ff size=2>Otherwise you would never know who it would end up with.
</FONT></SPAN></DIV>
<DIV dir=ltr align=left><SPAN class=794033506-16082006><FONT face=Arial
color=#0000ff size=2>If A substitutes to B who substitutes to
C</FONT></SPAN></DIV>
<DIV dir=ltr align=left><SPAN class=794033506-16082006><FONT face=Arial
color=#0000ff size=2>B can see B's items and A's items </FONT></SPAN></DIV>
<DIV dir=ltr align=left><SPAN class=794033506-16082006><FONT face=Arial
color=#0000ff size=2>C can see C's items and B's items but not A's
items</FONT></SPAN></DIV>
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<FONT face=Tahoma size=2><B>From:</B> sap-wug-bounces@mit.edu
[mailto:sap-wug-bounces@mit.edu] <B>On Behalf Of </B>Khanna,
Manish<BR><B>Sent:</B> Wednesday, 16 August 2006 4:03 PM<BR><B>To:</B> SAP
Workflow Users' Group<BR><B>Subject:</B> Substitutes of
Substitutes<BR></FONT><BR></DIV>
<DIV></DIV>
<DIV class=Section1>
<P class=MsoNormal><FONT face="Bookman Old Style" size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 'Bookman Old Style'">Hi,<o:p></o:p></SPAN></FONT></P>
<P class=MsoNormal><FONT face="Bookman Old Style" size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 'Bookman Old Style'"><o:p> </o:p></SPAN></FONT></P>
<P class=MsoNormal><FONT face="Bookman Old Style" size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 'Bookman Old Style'">As a substitute can
‘see’ the inbox of original approver, if a substitution is active. Is this
applicable for the substitute of substitute and so
on..<o:p></o:p></SPAN></FONT></P>
<P class=MsoNormal><FONT face="Bookman Old Style" size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 'Bookman Old Style'"><o:p> </o:p></SPAN></FONT></P>
<P class=MsoNormal><FONT face="Bookman Old Style" size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 'Bookman Old Style'">For
eg..<o:p></o:p></SPAN></FONT></P>
<P class=MsoNormal><FONT face="Bookman Old Style" size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 'Bookman Old Style'">B is substitute of A
with active substitution. Hence B can see A’s work
items.<o:p></o:p></SPAN></FONT></P>
<P class=MsoNormal><FONT face="Bookman Old Style" size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 'Bookman Old Style'"><o:p> </o:p></SPAN></FONT></P>
<P class=MsoNormal><FONT face="Bookman Old Style" size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 'Bookman Old Style'">And
if<o:p></o:p></SPAN></FONT></P>
<P class=MsoNormal><FONT face="Bookman Old Style" size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 'Bookman Old Style'"><o:p> </o:p></SPAN></FONT></P>
<P class=MsoNormal><FONT face="Bookman Old Style" size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 'Bookman Old Style'">B is substitute of A
with active substitution and C is substitute of B with active substitution. Does
C also see A’s work items?<o:p></o:p></SPAN></FONT></P>
<P class=MsoNormal><FONT face="Bookman Old Style" size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 'Bookman Old Style'"><o:p> </o:p></SPAN></FONT></P>
<P class=MsoNormal><FONT face="Bookman Old Style" size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 'Bookman Old Style'">Regards,<o:p></o:p></SPAN></FONT></P>
<P class=MsoNormal><FONT face="Bookman Old Style" size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: 'Bookman Old Style'">Manish<o:p></o:p></SPAN></FONT></P></DIV></BODY></HTML>