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<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'>Robert,<o:p></o:p></span></font></p>
<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'><o:p> </o:p></span></font></p>
<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'>My guess would be 01 branches required.
There’s only one way to find out and that would be to try 01, then 02.<o:p></o:p></span></font></p>
<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'><o:p> </o:p></span></font></p>
<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'>Richard…<o:p></o:p></span></font></p>
<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'><o:p> </o:p></span></font></p>
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<p class=MsoNormal><b><font size=2 face=Tahoma><span style='font-size:10.0pt;
font-family:Tahoma;font-weight:bold'>From:</span></font></b><font size=2
face=Tahoma><span style='font-size:10.0pt;font-family:Tahoma'>
sap-wug-bounces@mit.edu [mailto:sap-wug-bounces@mit.edu] <b><span
style='font-weight:bold'>On Behalf Of </span></b>robert.van.den.berg@accenture.com<br>
<b><span style='font-weight:bold'>Sent:</span></b> Monday, January 17, 2005
9:23 AM<br>
<b><span style='font-weight:bold'>To:</span></b> sap-wug@mit.edu<br>
<b><span style='font-weight:bold'>Subject:</span></b> Fork condition</span></font><font
size=3 face="Times New Roman"><span style='font-size:12.0pt;font-family:"Times New Roman"'><o:p></o:p></span></font></p>
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<p class=MsoNormal><font size=2 face="Book Antiqua"><span style='font-size:
11.0pt'><o:p> </o:p></span></font></p>
<p class=MsoNormal><font size=2 face=Tahoma><span style='font-size:10.0pt;
font-family:Tahoma'>Hello,</span></font><o:p></o:p></p>
<p class=MsoNormal><font size=2 face=Tahoma><span style='font-size:10.0pt;
font-family:Tahoma'> </span></font><o:p></o:p></p>
<p class=MsoNormal><font size=2 face=Tahoma><span style='font-size:10.0pt;
font-family:Tahoma'>Next question,</span></font><o:p></o:p></p>
<p class=MsoNormal><font size=2 face=Tahoma><span style='font-size:10.0pt;
font-family:Tahoma'> </span></font><o:p></o:p></p>
<p class=MsoNormal><font size=2 face=Tahoma><span style='font-size:10.0pt;
font-family:Tahoma'>This is the first time I want to work with a condition in a
fork.</span></font><o:p></o:p></p>
<p class=MsoNormal><font size=2 face=Tahoma><span style='font-size:10.0pt;
font-family:Tahoma'> </span></font><o:p></o:p></p>
<p class=MsoNormal><font size=2 face=Tahoma><span style='font-size:10.0pt;
font-family:Tahoma'>I have 2 branches. I one is finished, I want to check a
value of a containerelement. If the containerelement is filled with a certain value,
the fork other branch should be taken into the process. If the containerlement
is filled with another value, the second branch is important and should be
processed.</span></font><o:p></o:p></p>
<p class=MsoNormal><font size=2 face=Tahoma><span style='font-size:10.0pt;
font-family:Tahoma'> </span></font><o:p></o:p></p>
<p class=MsoNormal><font size=2 face=Tahoma><span style='font-size:10.0pt;
font-family:Tahoma'>Should I fill in “Branches required = 02” and
the condition, or should the “Branches required = 01” and the
condition??</span></font><o:p></o:p></p>
<p class=MsoNormal><font size=2 face=Tahoma><span style='font-size:10.0pt;
font-family:Tahoma'>Or doesn’t it work that way??</span></font><o:p></o:p></p>
<p class=MsoNormal><font size=2 face=Tahoma><span style='font-size:10.0pt;
font-family:Tahoma'> </span></font><o:p></o:p></p>
<p class=MsoNormal><font size=2 face=Tahoma><span style='font-size:10.0pt;
font-family:Tahoma'>Regards,</span></font><o:p></o:p></p>
<p class=MsoNormal><font size=2 face=Tahoma><span style='font-size:10.0pt;
font-family:Tahoma'>Robert</span></font><o:p></o:p></p>
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