[krbdev.mit.edu #2992] Kerberos 1.4 will not build gssapi_krb5.h on AIX 5.2

[James A Goodwin via RT]

Here are the results:

      echo "Creating gssapi.h" ;  h=gss$$; rm -f $h;  (echo "/* This is the
gssapi_krb5.h prologue. */";  echo "\" ;  echo "/* End of gssapi_krb5.h
prologue. */";  cat ./gssapi_krb5.hin )> $h &&  (set -x; mv -f $h
gssapi_krb5.h) ; e=$?; rm -f $h; exit $e

The problem seems to be that an earlier line in the makefile reads:

      include_stdint=\#include <stdint.h>

And the statement:

      echo "$include_stdint"

is turning into:

      echo "\"

For some reason, the # is being treated as the start of a comment even
though the \ character precedes it.  Unfortunately, my knowledge of make is
limited, so I'll have to leave it to others to determine the source of the
problem.  If there is other information you need from me, I'll be glad to
provide it.

Regards,

-James Goodwin
Software Engineer
IBM Business Consulting Services
jagoodwi at us.ibm.com
Phone: (281) 336 2578
Fax: (281) 335 4231
T/L 260-2578

"0000-Admin" <daemon at MIT.EDU> wrote on 03/30/2005 03:13:13 PM:

> >>>>> "James" == James A Goodwin via RT <rt-comment at krbdev.mit.edu>
writes:
>
> James> Initial make of Kerberos 1.4 fails with a Makefile syntax error:
>
> James> making all in lib/gssapi/krb5...
> James> /bin/sh: 0403-057 Syntax error at line 1 : `(' is not matched.
> James> make: 1254-004 The error code from the last command is 2.
>
> Could you please run "make -n gssapi_krb5.h" in that directory (after
> making sure that gssapi_krb5.h does not exist) using the original
> Makefile and send us the output?  There should not be an unbalanced
> left parenthesis there, unless the shell is parsing things weirdly, or
> the make program is doing something it shouldn't be doing.
>
> ---Tom
>